1 00:00:20,500 --> 00:00:25,600 The dance around the maypole is an ancient tradition probably originated in Germanic cultures 2 00:00:26,000 --> 00:00:38,000 Nowadays it is performed in folks festivals or as a children's game in many European and American countries 3 00:00:43,000 --> 00:00:48,000 The dancers twist the colored ribbons following precise movements 4 00:00:50,000 --> 00:00:55,000 Then they perform an inverse dance to undo the braid 5 00:00:58,000 --> 00:01:06,000 The ribbons can be braided in different ways and new choreography can generate new braids 6 00:01:14,000 --> 00:01:18,000 In fact dances and braids have a lot to do with each other 7 00:01:32,000 --> 00:01:37,000 Each of these dancers arrives in a colored position after each piece of the dance 8 00:01:41,000 --> 00:01:46,000 So, at the end, they occupy the same positions as at the beginning of the dance 9 00:01:47,000 --> 00:01:53,000 How can we keep track of the movements and make a static drawing that describes the dance? 10 00:01:54,000 --> 00:01:57,000 Let's formalize the dance 11 00:01:57,200 --> 00:02:00,000 Turn the dancers into points 12 00:02:04,000 --> 00:02:08,000 Let the points move in a disc 13 00:02:10,000 --> 00:02:16,000 At each moment the points are distinct: the dancers never collide! 14 00:02:19,000 --> 00:02:25,000 The points go back to their initial positions, but possibly they exchange places 15 00:02:29,000 --> 00:02:34,500 If we draw the path described by each point on the disc we can get a very complicated drawing 16 00:02:34,700 --> 00:02:44,000 We see some intersections and we don't know who passed there first So we can not reconstruct the dance 17 00:02:58,000 --> 00:03:04,000 A solution is to move the disc while the dance is being performed 18 00:03:04,500 --> 00:03:11,000 In other words, we transform time into a spatial dimension, in this case the vertical direction 19 00:03:12,000 --> 00:03:17,000 Of course in each moment we have the same number of dancers 20 00:03:17,200 --> 00:03:23,000 This means that at each level a horizontal disc will meet each path exactly once 21 00:03:24,000 --> 00:03:28,000 We have already seen diagrams like this: this is a braid! 22 00:03:30,000 --> 00:03:34,000 Following our convention, we should align the braid horizontally 23 00:03:34,200 --> 00:03:39,200 But just for this chapter we will change notation and draw braids vertically 24 00:03:44,000 --> 00:03:50,000 Vice versa, given any braid we can turn it into a dance 25 00:04:02,500 --> 00:04:07,800 In other words, we now have a description of braids as the trace of dancing points 26 00:04:08,000 --> 00:04:12,600 Braids and dances are the same thing! 27 00:04:17,000 --> 00:04:24,000 Now let's consider some particular dances where dancers are in pairs, always holding hands 28 00:04:25,000 --> 00:04:30,000 As before, all the positions held in the beginning have to be filled at the end of the dance 29 00:04:45,000 --> 00:04:50,000 This time, a pair of dancers becomes an arc 30 00:04:58,000 --> 00:05:03,000 The arcs move keeping the endpoints on a disc 31 00:05:03,500 --> 00:05:05,500 They can turn, 32 00:05:05,700 --> 00:05:07,700 exchange positions, 33 00:05:07,900 --> 00:05:10,500 pass one over other, and so on. 34 00:05:18,000 --> 00:05:22,000 As before, we can translate the dance into a braid 35 00:05:22,200 --> 00:05:30,000 We move the disc vertically and draw the paths described by the dancers, the endpoints of the arcs 36 00:05:53,000 --> 00:05:56,500 Which braids are dances of couples? 37 00:05:57,000 --> 00:06:07,000 Of course, the non-dance, where all the points stay still, is of this type So, the identity braid is a dance of couples 38 00:06:08,000 --> 00:06:13,000 Performing a dance after another corresponds to composition of braids 39 00:06:14,000 --> 00:06:19,000 Composing two dances of couples we get a new dance of the same type 40 00:06:20,000 --> 00:06:25,000 Also the inverse of a dance of couple is of the same type 41 00:06:36,000 --> 00:06:47,000 Then we say that braids describing dances of couples form a subgroup of the braid group. It is called the Hilden subgroup 42 00:06:53,000 --> 00:06:57,000 There are some simple dances in the subgroup: 43 00:06:57,500 --> 00:07:03,000 The two dancers within a single couple can exchange positions 44 00:07:08,500 --> 00:07:14,000 Two couples can exchange positions 45 00:07:20,500 --> 00:07:26,000 A couple can pass under the arms of another couple 46 00:07:29,000 --> 00:07:39,000 Many other dances can be performed, but in fact the three movements just described are sufficient to assemble all Hilden's dances 47 00:07:39,200 --> 00:07:44,000 In other words, these are the generators of the Hilden subgroup 48 00:07:45,000 --> 00:07:50,000 Finding the relations, as in the case of the braid group, is much more complicated 49 00:07:51,000 --> 00:07:53,000 What is all this good for? 50 00:07:53,200 --> 00:08:00,000 Recall that in chapter 3 we described a way to relate braids to knots, via the closure 51 00:08:01,000 --> 00:08:10,000 When we close a braid, we are actually adding new trivial strands and connecting each old strand with a new one, obtaining a knot 52 00:08:17,000 --> 00:08:25,000 If we move the new strands behind the old ones we obtain a different braid, closed in a new way 53 00:08:30,000 --> 00:08:39,000 This closure can be done on each braid with an even number of strands It is called the plat closure 54 00:08:40,000 --> 00:08:46,000 Again, closing a braid as a plat we obtain a knot 55 00:08:50,000 --> 00:08:56,000 Recall the Alexander theorem: any knot can be obtained by closing a braid 56 00:08:55,870 --> 00:09:01,000 We saw how to cut a knot to obtain a braid 57 00:09:04,000 --> 00:09:12,000 From the closed braid we can obtain a plat, thus any knot can be obtain as a closure of a plat 58 00:09:26,000 --> 00:09:34,000 Can we write a Markov theorem for the new closure? That is, which braids give the same knot via plat closure? 59 00:09:41,000 --> 00:09:42,000 We can do some simple moves: 60 00:09:43,000 --> 00:09:49,000 we can compose our plat with Hilden elements both on the bottom 61 00:09:49,500 --> 00:09:52,500 or on the top 62 00:09:54,000 --> 00:10:01,000 Moreover, we can add two strands and a crossing 63 00:10:02,000 --> 00:10:09,000 And go on like this, using Hilden elements and the new stabilization move 64 00:10:10,000 --> 00:10:22,000 When we close the plat, the knot type will not change: we can retract the arcs and obtain the initial knot 65 00:10:40,000 --> 00:10:44,000 Birman showed that these moves are enough: 66 00:10:44,000 --> 00:10:49,190 two plats give the same knot if and only if they can be turned into each other through a sequence of moves of the two types 67 00:10:53,000 --> 00:10:59,000 So the Hilden subgroup, that is the dances of couples, is one of the main ingredients of this theorem! 68 00:11:00,000 --> 00:11:04,500 Now a question arises: how can we recognize the Hilden elements? 69 00:11:05,000 --> 00:11:09,000 For example, this is a dance of couples 70 00:11:14,000 --> 00:11:18,000 This is a Hilden braid, too 71 00:11:23,000 --> 00:11:30,000 This is not, since single dancers of different couples can not exchange positions 72 00:11:33,000 --> 00:11:40,000 But in general, given a braid with an even number of strands how can we check if it belongs to the Hilden subgroup? 73 00:11:40,500 --> 00:11:45,000 This is one of the classic problems in combinatorial group theory 74 00:11:46,000 --> 00:11:50,000 In the case of the Hilden subgroup there is a way to answer That is, there is an algorithm 75 00:11:50,200 --> 00:11:56,200 But in general, in less peculiar groups, there can not exist such an algorithm! 76 00:11:57,000 --> 00:12:00,500 Again, we have bumped into an algorithmic problem! 77 00:12:00,700 --> 00:12:05,700 And again, we have found a connection with knot theory